The prime factorisation of 110 is 2*5*11.
Therefore all factors of 110 are 2p*5q*11r where each of p, q and r can be 0 or 1.
The prime factorisation of 110 is 2*5*11.Therefore all factors of 110 are 2p*5q*11r where each of p, q and r can be 0 or 1.
The question could only be answered if I knew what I was supposed to demonstrate. But since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.
The prime factors of 110 are 2, 5 and 11.
110 has eight factors: 1 2 5 10 11 22 55 110.
The factors of 110 are: 1, 2, 5, 10, 11, 22, 55, 110.
2, 5, 11
1, 2, 5, 10, 11, 22, 55, 110
All Factors of 110:1, 2, 5, 10, 11, 22, 55, 110
Find the prime factorisation of 110.Find all possible combinations of these. Done!
Write down 1 and 110. Divide by two. Write down 55 and 2. Divide by five. Write down 11 and 10. Divide by two. Write down 5 and 22. Stop. Arrange them in ascending order. 1, 2, 5, 10, 11, 22, 55, 110
The term common factors specifically refers to the factors shared by two or more numbers. Since 109 is a single number, you could say that it shares all of its factors with itself.109 is a prime number. It is only evenly divisible by itself and one.
110/1 = 110 110/2 = 55 110/5 = 22 110/10 = 11 1, 2, 5, 10, 11, 22, 55, 110