It is not possible to give all the multiples of any number (other than zero) since there is no end to them.
If x were the largest multiple of 145 then
x+145 is a multiple of 145 and it is larger than x.
So x is not the largest multiple of 145. So there are an infinite number of multiples.
The first 15 multiples of 145:
145, 290, 435, 580, 725, 870, 1015, 1160, 1305, 1450, 1595, 1740, 1885, 2030, 2175 . . .
The multiples of 145 (which are infinite) are all divisible by 145, including these: 145, 290, 435, 580, 725, 870, 1015, 1160, 1305 . . .
The multiples of 145 (which are infinite) are all divisible by 145 , including these: 290, 435, 580, 725, 870, 1015, 1160, 1305, 1450 . . .
The first 15 multiples of 145: 145, 290, 435, 580, 725, 870, 1015, 1160, 1305, 1450, 1595, 1740, 1885, 2030, 2175 . . .
Common multiples include any multiple of 870.
The multiples of 29 are numbers that can be divided evenly by 29 without leaving a remainder. These multiples follow a pattern where each multiple is obtained by multiplying 29 by a natural number (1, 2, 3, ...). So, the multiples of 29 are 29, 58, 87, 116, 145, and so on.
35, 70, 115, 145, 180...
145, 290, 435, 580, 725, 870, 1015, 1160, 1305, 1450, 1595, . . .
29, 58, 87, 116 & 145
The total number is infinite. The first 10 are: 145, 290, 435, 580, 725, 870, 1015, 1160, 1305, 1450 . . .
They are all the multiples of 16.They are all the multiples of 16.They are all the multiples of 16.They are all the multiples of 16.
29, 58, 87, 116, 145, 174, 203, 232, 261, 290 . . .
There is only one LCM, so it cannot be A lcm, but possibly THE lcm. The LCM of any two (or more) numbers MUST be a multiple of all the numbers. For 15 and 18 the LCM must be a multiple of both 15 and 18. In particular it must be one of the multiples of 18. 18 is an even number, so all its multiples will be even. 145 is an odd number, so it cannot be a multiple of 18 Thus 145 cannot be a multiple of both 15 and 18. Thus it cannot be the LCM of 15 and 18. QED.