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How many positive integers from 1 to 1000 inclusive are there such that is a multiple of 3 and the digit sum of is also a multiple of 3?
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
How many positive integers n from 1 to 1000 inclusive are there such that n is a multiple of 3 and the digit sum of n is also a multiple of 3?
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
What are all the multiples of 81 up to 1000?
81, 162, 243, 324, 405, 486, 567, 648, 729, 810, 891, 972.
Multiples of 3 greater than 400?
403 406 409 412 and so on These are NOT multiples of three, none of them are. Any multiple of three has to have all individual numbers add up to three like 423 4+2+3=9 423/3 = 141
One half of the sum of three consecutive multiples of 10 is 90 What are the multiples of 10?
If half of the sum is 90 then the full sum must be 180. The three consecutive multiples of 10 which add up to 180 are 50, 60 and 70.
What is a multiples of 25 up to 1000?
Multiples of 25 up to 1000 are: 25;50;75;100;125;150;175;200;225;250;275;300;325;350;375;400;425;450;475; 500;525;550;575;600;625;650;675;700;725;750;775;800;825;850;875;900;925;950;975;1000
What are all the numbers of that you can multiply by 3 to get up to 1000?
All of its multiples from 3 to 999
What are some numbers that are multiples or 3 and 4 up to 1000?
All multiples of 12, such as 120, 600, 660.
How many multiples of 4 are there up to 1000?
250
What are multiples of 7 up to 1000?
There are 143 such numbers, too many to list.
What is the sum of all the multiples of 3 or 5 below 1000?
The first multiple of 3 is 3; the last multiple of 3 below 1000 is 999. (This can be determined by dividing 1000 by 3, ignoring the remainder, and then multiplying that number by 3 to determine the largest multiple of 3 less than 1000.) Since 999 is 3 times 333, there are 333 multiples of 3 that are less than 1000. So, consider them by pairs: 1st and 333rd = 3 + 999 = 1002 2nd and 332nd = (2 x 3) + (332 x 3) = 6 + 996 = 1002 3rd and 331st = (3 x 3) + (331 x 3) = 9 + 993 = 1002 up to 166th and 168th = (166 x 3) + (168 x 3) = 498 + 504 = 1002 167th = 501 (which is half of 1002) In other words, since 333 is not an even number, there are (333 - 1)/2 = 166 pairs, plus that extra half of a pair. The sum of all the multiples of 3 less than 1000 is 166.5 x 1002 = 166,833. The same can be done for the multiples of 5. The first multiple of 5 is 5; the last multiple of 5 below 1000 is 995. (This can be determined by dividing 1000 by 5, subtracting 1 since it divided evenly and you need the largest multiple less than 1000, and then multiplying that number by 5 to determine the largest multiple of 5 less than 1000.) Since 995 is 5 times 199, there are 199 multiples of 5 that are less than 1000. So, consider these by pairs as well.e are 1st and 199 = 5 + 995 = 1000 2nd and 198 = 10 + 990 = 1000 up to 100th = 500 (which is half of 1000) In other words, since 199 is not an even number, there are (199 - 1)/2 = 99 pairs, plus that extra half of a pair. So, the sum of all the multiples of 5 less than 1000 is 99.5 x 1000 = 99,500. If the desired answer is the sum of all numbers less than 1000 that are either multiples of 3 or 5, then the numbers that are multiples of both 3 and 5 have been included twice - once as multiples of 3 and again as multiples of 5. So, since all numbers that are both multiples of 3 and multiples of 5 are multiples of 15, determine the sum of all the multiples of 15 and subtract it from the sum of the multiples of 3 and the multiples of 5. We can repeat the same procedure again. The first multiple of 15 is 15; the last multiple of 15 less than 1000 is 990. Since 990 is 15 x 66, there are 66 multiples of 15 less than 1000. 1st and 66th = 15 + 990 = 1005 2nd and 65th = 30 + 975 = 1005 and so on Since 66 is an even number, there are 66/2 = 33 pairs. So the sum of all the multiples of 15 less than 1000 is 33 x 1005 = 33,165. The sum of all the multiples of 3 and all the multiples of 5, but not counting them twice, is 166,833 + 99,500 - 33,165 = 233,168.
What are the multiples of 20 up to 1000?
20, 40, 60, 80, 100, 120 and just keep adding 20 until you get to 1000
What are all the even numbers up to 60 that are multiples of 3?
They are all te multiples of 6 within that range.
How many multiples of 3 are there between 1 and 1001 and show work?
I would do it like this though I'm sure there are other ways: There are 10 multiples of 3 every 30 (3,6,9,12,15,18,21,24,27,30). There are (1000/30)= 33 lots of 30 in 1000 Therefore there are (10 x 33)=330 multiples of 3 which brings us up to 990 (330x3 =990) Then there are 3 more multiples of 3 993, 996,999 This makes the total 333 multiples of three between 1 and 1001
Are all multiples of 3 also multiples of 9?
Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.
What are all the odd numbers up to 5000 that are multiples of 4?
No odd numbers are multiples of 4.
What are the similarities of multiples of 3?
All multiples of 3 have digits that add up to a multiple of 3.
