2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113.
120 = 2*2*2*3*5, so there is 5 prime numbers, no 2 prime numbers
If it's right, the numbers will all be prime and multiply to 120. 2 x 2 x 2 x 3 x 5 = 120
2 x 2 x 2 x 3 x 5 = 120
They are: 97+23 = 120 or 2*2*2*3*5 = 120
The Prime Factors of 120 are: 2 x 2 x 2 x 3 x 5
They are: 2*2*2*3*5 = 120
2, 3 and 5
Start by listing out all pairs of numbers greater than 0 and less than or equal to 120 that have a product equal to 120:120 = 1 x 120120 = 2 x 60120 = 3 x 40120 = 4 x 30120 = 5 x 24120 = 6 x 20120 = 8 x 15120 = 10 x 12So, there are 8 factor pairs of 120. Now, show the prime factorization for 120 by expressing it as the product of ALL prime numbers:120 = 2 x 60
2 x 2 x 2 x 3 x 5 = 120
240
All prime numbers are not odd numbers. 2 is an even prime number, and it is the only even prime number because all other even numbers have 2 as one of their factors.
Yes and they are: 2 2 2 3 and 5