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The input stream to a 4B5B block encoder is 0100 0000 0000 0000 0000 OOOI.?
The 4B5B encoding process converts each 4-bit group of the input stream into a corresponding 5-bit output. For the input sequence "0100 0000 0000 0000 0000 OOOI," the encoder will take each 4-bit segment (like "0100" and "0000") and map them to their respective 5-bit codes according to the 4B5B encoding scheme. The "O" and "I" at the end seem to be placeholders or invalid inputs, as 4B5B requires groups of four bits for proper encoding. The resulting output will be a sequence of 5-bit codes corresponding to each valid 4-bit input segment.
What are the line coding methods?
· 4B3T · 4B5B · 2B1Q · Hamming Code · 8b/10b encoding · 64b/66b encoding · 6b/8b encoding · 64b/66b encoding · MPlus used in DVD · Eight-to-Fourteen Modulation (EFM) used in Compact Disc · Conditioned Diphase · Coded mark inversion (CMI) · EF Carrier Suppressed Return-to-Zero Optical line code. · Alternate-Phase Return-to-Zero
What is 4B4B data mapping?
Perhaps you mean 4B5B? That's a way to assign combinations of 5 bits to every combination of 4 bits, in such a way that you avoid transmitting long strings of only zeros or only ones. This avoids synchronization problems.
Show the equivalent 4B5B code of the bit string 1101 1010 0011 0001 1000 1001?
1101 => 11011 1010 => 10110 0011 => 10101 0001 => 01001 1000 => 10010 1001 => 10011 and together: 11011 10110 10101 01001 10010 10011
