1 3 7 9 21 63.
Six factors.
1 3 7 9 21 63.
1, 3, 7, 9, 21, 63.
All odd numbers with one or two distinct prime factors are deficient. Since 3 and 7 are factors of 63, it must be deficient.
The 6 factors of 63 are 1, 3, 7, 9, 21, and 63. The factor pairs of 63 are 1 x 63, 3 x 21, and 7 x 9. The proper factors of 63 are 1, 3, 7, 9, and 21; possibly not 1, depending on your definition. The prime factors of 63 are 3, 3, and 7. The 2 distinct prime factors of 63 are 3 and 7.
49 has one distinct prime factor, two altogether.
49 has one distinct prime factor, two altogether.
49 has one distinct prime factor, two altogether.
The factors of 63 are: 1, 3, 7, 9, 21, 63. The prime factors of 63 are: 3, 7
Six distinct factors Two distinct prime factors
100 and 63 both have two distinct prime factors. (The others only have one.) 100 = 2*2*5*5 63 = 3*3*7 49 = 7*7 32 = 2*2*2*2*2
the factors for 63 is 1 3 7 9 21 and 63