1, 3, 9, 71, 213, 639
Six factors.
639 is a composite number. Its positive integer factors are: 1, 3, 9, 71, 213, 639
1, 639 Then by inspection of the number 639 , we note that each number is a multiple of '3' . So '3' is a factor. Also , slightly more 'tricky'. If we add the digits of 639 ; 6 + 3 + 9 = 18 1 + 8 = 9 . This means that the number has '9' is a factor. NB This only applies to factors/multiples of '9' Finally, divide 639 by 71 and/or 213 . If you have a whole number answer (No decimals), then those numbers are also factors of 639. Hence 639/71 = 9 & 329 / 213 = 3 So allthe given numbers are factors of 639.
3 x 3 x 71 are the prime factors. You should now be able to calculate the composites...
1, 3, 9, 27, 71, 213, 639, 1917
The factors of 1,278 are: 1 2 3 6 9 18 71 142 213 426 639 1278
The factors of 1278 are: 1, 2, 3, 6, 9, 18, 71, 142, 213, 426, 639, 1278
The factors of 1,278 are: 1 2 3 6 9 18 71 142 213 426 639 1,278
Separate the number into prime factors. Then it should be easy to get ALL the factors, simply by combining different prime factors.
The factors of 1278 are: 1, 2, 3, 6, 9, 18, 71, 142, 213, 426, 639, 1278.
639 ÷ 3 = 213
639 divided by 3 = 213 So 213 x 3 = 639