Q: What are four consecutive odd integers whose sum is 144?

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The integers are 144 and 145.

146

x+(x+1)+(x+2)=-144 x+x+1+x+2=-144 3x+3=-144 -3 -3 3x=-147 --- --- 3 3 x= -49 -49, -48, -47

To sum the integers: 1 + 2 + 3 + 4 + 5 + . . . . . + 142 + 143 + 144 = ?The 1st and last: 1 + 144 = 145The 2nd and second-last: 2 + 143 = 145The 3rd and third-last: 3 + 142 = 145The 4th and fourth-last: 4 + 141 = 145The 5th and fifth-last: 5 + 140 = 145There are (144/2) = 72 pairs.Each pair adds to 145.The total is (72 x 145) = 10,440

Try it out! See whether it is divisible by different integers (starting at 2) - up to the square root of 144 in this case. If you find that it is divisible by some positive integer (other than 1 and 144), it is NOT a prime. Otherwise it is.

Related questions

The integers are 144 and 145.

146

The integers are 12 and 14 (144+196=340)

144 + 196 = 340 so integers are 12 & 14.

438

x+(x+1)+(x+2)=-144 x+x+1+x+2=-144 3x+3=-144 -3 -3 3x=-147 --- --- 3 3 x= -49 -49, -48, -47

No, it is an integer; all integers are rational.

To sum the integers: 1 + 2 + 3 + 4 + 5 + . . . . . + 142 + 143 + 144 = ?The 1st and last: 1 + 144 = 145The 2nd and second-last: 2 + 143 = 145The 3rd and third-last: 3 + 142 = 145The 4th and fourth-last: 4 + 141 = 145The 5th and fifth-last: 5 + 140 = 145There are (144/2) = 72 pairs.Each pair adds to 145.The total is (72 x 145) = 10,440

fDF

It is an angle whose measure is 144 degrees!

5x5=144

137