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To sum the integers: 1 + 2 + 3 + 4 + 5 + . . . . . + 142 + 143 + 144 = ?

The 1st and last: 1 + 144 = 145

The 2nd and second-last: 2 + 143 = 145

The 3rd and third-last: 3 + 142 = 145

The 4th and fourth-last: 4 + 141 = 145

The 5th and fifth-last: 5 + 140 = 145

There are (144/2) = 72 pairs.

Each pair adds to 145.

The total is (72 x 145) = 10,440

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Q: What are the sum of consecutive integers of 144?
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