Let x be 1st no.
x+2 2nd no.(as there is a diff. of 2 no b/w 2 odd no)
x+4 and x+6 the 3rd and 4th
acc. to the ques,
x+x+2+x+4+x+6=1001
4x+12=1001
x=(1001-12)/4
x=247.25
thus,
247.25,249.25,251.25,253.25 are the 4 odd no 998+1+1+1=1001
The smallest four digit odd integer is 1001.
There are no such numbers.
There are no four odd numbers that will add up to nineteen.
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
23
You get an even number
The numbers are 57, 59, 61 and 63.
The first odd number is 1001, the last odd number is 99999; thus there are: (99999 - 1001) ÷ 2 + 1 = 49500 of them.
They are all the 4 digit numbers starting with 1 and ending with 1, 3, 5, 7 or 9. Since there are 500 of them, I will not list them.
An odd number of odd numbers can not add up to an even number. There fore any 9 (odd) odd numbers can not add up to 50 (even).
17, 19, 21 and 23.
1 + 3 + 5 + 71 there are many combinations