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Q: What are multiples of 9 that are also multiples of 2?

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No; all multiples are not multiples of 6, for example 3×3 = 9 is not a multiple of 6. However as 6 = 2×3 all multiples of 6 are also multiples of 3.

Yes, all multiples of 9 are also multiples of 3.but they're not all of them. Every multiple of 9 is also a multiple of 3, but there are more multiples of 3 besides those.

Yes, multiples of 8 are also multiples of 2 because 8 is a multiple of 2 itself.

All multiples of 16 are also multiples of 2.

No. For a start, 9 is itself a multiple of 9, but it is not a multiple of 6.In general, all multiples of a number "a" will also be multiples of number "b", only if "a" itself is also a multiple of "b". For example, all multiples of 12 are multiples of 4, since 12 is a multiple of 4.

multiples of 8 are also multiples of 2 because anything you times by 8 is an even number

"The" five multiples is wrong; there are infinitely many multiples for any number (except zero), not just five. To get those multiples, just use the definition of multiple. That is, you can do any of the following multiplications: 9 x 0 9 x 1 9 x 2 9 x 3 etc., also: 9 x (-1) 9 x (-2) etc.

18

Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.

Yes.

All multiples of 8 are also multiples of 2, but not all multiples of 2 are multiples of 8.

Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72

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