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Q: Are all multiples of 9 also multiples of 3?

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Yes, but that doesn't cover all of them. Every multiple of 9 is also a multiple of 3, but there are more multiples of 3 besides those.

Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.

there are too many! like 9, 18, 27, 36,...basially, all the multiples of nine are also multiples of 3.

The first three multiples of 3 are 3, 6, 9 The first three multiples of 9 are 9, 18, 27 As the lowest common multiples of 3 and 9 is 9, the common multiples of 3 and 9 are the multiples of 9, thus: The first three common multiples of 3 and 9 are 9, 18, 27

No. For example 9 times 3 is 27 but you cant multiply 6 by any hole number to get 27. Hope it helps. :D

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No; all multiples are not multiples of 6, for example 3×3 = 9 is not a multiple of 6. However as 6 = 2×3 all multiples of 6 are also multiples of 3.

Yes, but that doesn't cover all of them. Every multiple of 9 is also a multiple of 3, but there are more multiples of 3 besides those.

Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.

yes, every multiple of 9 is a multiple of 3, but that doesn't cover all of them ...there are more multiples of 3 besides those.

there are too many! like 9, 18, 27, 36,...basially, all the multiples of nine are also multiples of 3.

yes since 9 is divisible by 3 all its multiples are as well

3, 9, and 15. 6 and 18 are also multiples of 3, but are even.

3 yes, 6 no.

The numbers 3,6 and 9 are all multiples of 3 because 3 can go into all of them evenly.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

18 and all the multiples of 18.

This question is true

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