That's an infinite list that includes 20 + 20, 32 + 8, and 14 + 26
18
40 and 9
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
They are: 3+37 = 40
They are 40 and 40
no 3 numbers add to equal 10 and multiply to equal 40.
How about: 17+23 = 40 as one example
The numbers are 96 and 40
-452
26
The two numbers that add to -6 and multiply to -40 are -10 and 4. This is because -10 + 4 = -6 and -10 * 4 = -40. This type of problem can be solved by setting up a system of equations where the sum of the numbers is -6 and the product of the numbers is -40, then solving for the two numbers.
-34