The midpoint divides a line segment in half.
divide the line segment in half to aquire the center point
No, because if there is more than one midpoint then it will be like multiple line segments connected together. You can't have two midpoints or more, but you can have one to divide the line segment in half.
Yes.
The only diameter would be a line segment connecting the end points of the half-circle arc.
i don't know if you tell me I'll give u 50 points
1 Mark three points anywhere on the circumference of the circle. Designate these points A, B and C. It doesn't matter where you put these points, but the farther they are from each other, the more accurate your calculations will be2 Draw a line connecting points A and B. Call this line AB. Do the same with points B and C to create line BC.3 Find the center of line AB and BC. You can either measure the distance and divide it in half or use geometry and bisect the lines. You can use a compass set at a distance greater than half the length of the line segment and make arcs above and below the line segment. Do this from both endpoints to form points above and below the line segment, then connect these points to divide the line segment in half. Mark these middle points D and E.4 Draw perpendicular lines from points D and E using the compass technique or using a protractor to find a 90-degree angle. Where these lines intersect is the center of the circle.Tips & WarningsYou can check that you have found the center of the circle. Simply measure from the point you found to the edge of the circle. Pick a few different points. If they are all the same distance, you have found the center.
At the end of the line there needs to be two points. Measure the line and divide by two.
A segment between two points on a circle is
A segment with end points on a circle is a chord of that circle.
A line segment has end points
An Chord is a segment with end points on the circle. Your welcome. :)
A line segment is a line with two points. When drawn, there are no arrows coming out of the points.