2 and 19 are the prime factors of 38
Let's fix the question. What are the prime factors of 38? 38 = 2 x 19 the prime factors of 38 are 2 and 19.
The factors of 38 are 1, 2, 19, and 38. There are four different factors. The prime factors of 38 are 2 and 19. There are two different prime factors.
The prime factorization of 38 is 2 x 19.
The prime factors of 38 are 2 and 19. Since 1 isn't prime or composite, 1 is not a prime factor of 38. The prime factors of 38 are 19 and 2. Since 1 isn't prime or composite, 1 cannot be a prime factor of 38. 2 and 19
38 is a composite number; it has factors other than 1 and itself. It is not a prime number.The 4 factors of 38 are 1, 2, 19, and 38.The factor pairs of 38 are 1 x 38 and 2 x 19.The proper factors of 38 are 1, 2, and 19 or,if the definition you are using excludes 1, they are 2 and 19.The prime factors of 38 are 2 and 19.The 2 distinct prime factors (listing each prime factor only once) of 38 are 2 and 19.The prime factorization of 38 is 2 x 19.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple of a single number because "common" refers to factors or multiples that two or more numbers have in common.
Yes, you can write 38 as a product of prime factors. Since it is an even number, you can start by dividing 38 by 2. Your answer is 19. Since 2 and 19 are prime numbers, you are done. Prime factorization of 38 is: 2 X 19 = 38
The prime factors of 38 are 19 and 2. Since 1 isn't prime or composite, 1 cannot be a prime factor of 38.
It is: 2*19 = 38
The prime factors of the number 38 are 2 and 19.
1, 2, 19, 38 1, 2, 31, 62 2, 19 and 31 are prime.
Prime factors for: 38= 2 x 19 42= 2 x 3 x 7