To be divisible by both 4 and 9 a number must be a multiple of the Least Common Factor of 4 and 9. The LCM is 36.
The first 3 digit number in each hundred that is a multiple of 36 are as follows :-
108, 216, 324, 432, 504, 612, 720, 828 and 900.
Every three-digit number that ends with a zero or a 5 is divisible by 5.It doesn't matter what the first 2 digits are.
50% of numbers divisible by 5 are even, the other 50% are odd. If the single's digit of a number is 5, then the number is divisible by 5 and odd. For example, 25. However, if the single's digit of a number is 0, then the number is divisible by 5 and even. For example, 20.
Here are some of them: 10,010 10,021 10,032 and 10,043.
925 is a number divisible by 5, as its last digit is a 5. It is an odd number. Its divisors are 5, 5, and 37, also all odd numbers. It is a three-digit number.
300600900are some
All 2 digit numbers are divisible by 7: it is simply that some of the quotients are not whole numbers. 10/7 = 1 3/7 99/7 = 14 1/7 So the number of 2-digit numbers which are evenly divisible by 7 are 14-1 = 13.
Numbers are neither polite nor impolite; they simply are.
There are many. Some are: 100, 104, 108, 112, 116, 120.
Some numbers are divisible by 2 and Some are not.
All numbers divisible by 9 are divisible by 3, so you want all multiples of 9 that are 5 digit numbers. 10000 ÷ 9 = 11111/9 → first multiple of 9 that is a 5 digit number is 1112 x 9 = 10008 100000÷ 9 = 111111/9 → last multiple of 9 that is a 5 digit number is 11111 x 9 = 99999 → there are 11111 - 1112 + 1 = 10,000 five digit numbers that are divisible by 9 (and 3). I'll let you work some out (hint: multiple any number between 1112 and 11111 inclusive by 9).
You can always tell a number is divisible by eight by checking to see if the rightmost three digits are. If they are, then the whole number is. With that in mind then, you can make up all sorts of such numbers by just grabbing some combination that you know is divisible by eight, and tacking additional digits on to the left. For example, we know that 128 is divisible by eight (128 / 8 = 16), so any of these numbers are as well: 89469128 13948128 90173128 The number of digits doesn't matter, so we also know that a ridiculously large number like this one: 25098174509840582437575109283102477568758134024 is divisible by eight, because the last three digits are.
105, 120, 135 and so on.