1 2 3 5 6 10 15 25 30 50 75 150.
Twelve distinct factors.
The prime factorization of 150 is 2 * 3 * 5^2. The distinct prime factors are 2, 3, and 5. To find the product of these distinct prime factors, you simply multiply them together: 2 * 3 * 5 = 30. Therefore, the product of the distinct prime factors of 150 is 30.
1,2,3,4,6 and 12
The factors of 12 are: 1, 2, 3, 4, 6, 12
28.
The common factors of 12 and 150 are 1, 2, 3, and 6 .
12 distinct factors: 1 2 3 4 6 8 9 12 18 24 36 72.
The distinct factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.
Nine distinct factors: 1 2 3 4 6 9 12 18 36.
6
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 are the distinct factors of 60.
Six distinct factors Two distinct prime factors