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What are the chances of drawing four aces in a row from a shuffled deck of cards?
Wiki User
∙ 11y ago
(4/52) (3/51) (2/50) (1/49) = 24/6497400 = 1/270725 ~= 0.000003694
Wiki User
∙ 11y ago
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When two full packs of cards are used what are the chances of drawing an ace?
Since every full pack has four aces, there would be eight aces in two packs. You would have a very good chance of drawing one or more aces.
What is the probability of drawing two consecutive aces from a deck of fifty-two cards?
It is 1/221. Assume that the standard deck is completely shuffled in a completely unbiased way. The probability of drawing the first ace is 4/52, since there are 4 aces in a standard deck. The probability of drawing the second ace is 3/51, since there are three aces remaining and 51 cards from which to choose. 12/52 X 51 equals 12/2652, which equals 1/221.
What are chances of pulling 4 aces out 52 cards?
[original answer] four in 52! ==== The question is not fully stated, but I assume what is being asked is "What are the chances of pulling all four aces out of 52 cards when four cards are drawn". The answer is 1 / 270725 = 0.00000369 = 0.000369%. Approximately four out of one million. The chances are (4*3*2*1) / (52*51*50*49) = 24 / 649700 = 1 / 270725. That is, on the first draw there is a 4/52 chance of drawing one of the four aces out of the full pack; In the 48 out of 52 cases where an ace isn't drawn, "you lose". In the 4/52 cases where an ace is drawn first, there is a 3/51 chance of drawing one of the remaining three aces from the remaining 51 cards. If that happens, there is a 2/50 chance of drawing one of the remaining two aces from the remaining 50 cards; and then a 1/49 chance of drawing the last ace out of the remaining 49 cards. [ If the question is "What are the chances of pulling any of the aces out of 52 cards in one draw" then "four in 52" is correct. ]
What are the chances of not picking ace out of 52 cards?
There are four Aces in a standard deck of 52 cards. The probability, then, of not drawing an Ace is (52 - 4) in 52, or 48 in 52, or 12 in 13, or about 0.9231.
What is the probability of drawing an ace from a pinochle deck?
A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
What is the probability of drawing an ace or a king?
There are 52 cards in a deck there are 4 aces and 4 kings which makes a total of 8 kings and aces. Assuming that the deck is full and shuffled the probability of drawing an aces or a king is 8/52 which simplifies to 2/13
When two full packs of cards are used what are the chances of drawing an ace?
Since every full pack has four aces, there would be eight aces in two packs. You would have a very good chance of drawing one or more aces.
What is the probability of drawing two consecutive aces from a deck of fifty-two cards?
It is 1/221. Assume that the standard deck is completely shuffled in a completely unbiased way. The probability of drawing the first ace is 4/52, since there are 4 aces in a standard deck. The probability of drawing the second ace is 3/51, since there are three aces remaining and 51 cards from which to choose. 12/52 X 51 equals 12/2652, which equals 1/221.
What are chances of pulling 4 aces out 52 cards?
[original answer] four in 52! ==== The question is not fully stated, but I assume what is being asked is "What are the chances of pulling all four aces out of 52 cards when four cards are drawn". The answer is 1 / 270725 = 0.00000369 = 0.000369%. Approximately four out of one million. The chances are (4*3*2*1) / (52*51*50*49) = 24 / 649700 = 1 / 270725. That is, on the first draw there is a 4/52 chance of drawing one of the four aces out of the full pack; In the 48 out of 52 cases where an ace isn't drawn, "you lose". In the 4/52 cases where an ace is drawn first, there is a 3/51 chance of drawing one of the remaining three aces from the remaining 51 cards. If that happens, there is a 2/50 chance of drawing one of the remaining two aces from the remaining 50 cards; and then a 1/49 chance of drawing the last ace out of the remaining 49 cards. [ If the question is "What are the chances of pulling any of the aces out of 52 cards in one draw" then "four in 52" is correct. ]
What are the chances of not picking ace out of 52 cards?
There are four Aces in a standard deck of 52 cards. The probability, then, of not drawing an Ace is (52 - 4) in 52, or 48 in 52, or 12 in 13, or about 0.9231.
What is the probability of drawing an ace from a pinochle deck?
A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
What is the probability of drawing two consecutive aces from a deck of fifty two cards?
If you are drawing only two cards, the probability that they will both be aces is one in 221. ( (52 / 4) * (51 / 3) ) If you are drawing all the cards in the deck, one at a time, the probability that you will draw at least two aces in a row is much better than that, but how much better I leave for someone else to answer.
In a standard deck of 52 playing cards what is the probability of drawing an ace on one draw?
The probability of drawing one of the four aces on one draw in a standard deck of 52 cards is 1 in 13 (7.7 percent). This is calculated as such: there are 4 ace cards in a deck, which means the chances are 4/52, which reduces to 1/13.
What is the probaility of drawing a ace from a deck of cards?
Probability is 4 aces/52 total cards = 1/13 = .07692
What are the chances of drawing 4 aces in a row without replacement in a 52 card deck of cards?
It is (4/52)*(3/51)*(2/50)*(1/49) = 1/270,725 = 0.0000037 approx.
What is the probability of drawing a ace from a normal deck of cards?
Since there are 4 aces is a normal deck of 52 cards, the probability of drawing an ace is 4 in 52, or 1 in 13.
What is the probability of drawing an ace in a deck of 52 cards?
there are 4 aces in a deck, and 52 cards, so the probability is 4/52
