[original answer] four in 52!
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The question is not fully stated, but I assume what is being asked is "What are the chances of pulling all four aces out of 52 cards when four cards are drawn".
The answer is 1 / 270725 = 0.00000369 = 0.000369%. Approximately four out of one million.
The chances are (4*3*2*1) / (52*51*50*49) = 24 / 649700 = 1 / 270725. That is, on the first draw there is a 4/52 chance of drawing one of the four aces out of the full pack; In the 48 out of 52 cases where an ace isn't drawn, "you lose".
In the 4/52 cases where an ace is drawn first, there is a 3/51 chance of drawing one of the remaining three aces from the remaining 51 cards. If that happens, there is a 2/50 chance of drawing one of the remaining two aces from the remaining 50 cards; and then a 1/49 chance of drawing the last ace out of the remaining 49 cards.
[ If the question is "What are the chances of pulling any of the aces out of 52 cards in one draw" then "four in 52" is correct. ]
Prob(At least one ace in ten cards out of 52) = 1 - Prob(No aces in ten cards out of 52) When you start there are 48 non-ace cards out of 52, At the next draw, there are 47 non-ace cards out of 51, and so on = 1 - (48/52)*(47/51)* ... *(39/43) = 1 - 0.41 = 0.59
There are four Aces in a standard deck of 52 cards. The probability, then, of not drawing an Ace is (52 - 4) in 52, or 48 in 52, or 12 in 13, or about 0.9231.
There are 4 Aces in a deck of 52 cards.4
There are two red aces in a deck of 52 cards.
There are four aces in a deck, one of each suit.
Prob(At least one ace in ten cards out of 52) = 1 - Prob(No aces in ten cards out of 52) When you start there are 48 non-ace cards out of 52, At the next draw, there are 47 non-ace cards out of 51, and so on = 1 - (48/52)*(47/51)* ... *(39/43) = 1 - 0.41 = 0.59
There are four Aces in a standard deck of 52 cards. The probability, then, of not drawing an Ace is (52 - 4) in 52, or 48 in 52, or 12 in 13, or about 0.9231.
There are 4 Aces in a deck of 52 cards.4
There are two red aces in a deck of 52 cards.
The probabilty of pulling a queen out of a stack of cards is four chances (since there are four queens, one of each suit) out of 52. Or 4/52, or .08, or 8%.
The ratio of aces to all cards in a deck of 52 cards can be calculated as 4 aces out of 52 total cards. This simplifies to 1 ace for every 13 cards in the deck. Therefore, the ratio of aces to all cards in the deck is 1:13.
In a standard deck of 52 cards, there are two black aces: the Ace of Spades and the Ace of Clubs. These two cards are the only aces that are black in color, as the other two aces (Ace of Hearts and Ace of Diamonds) are red. So, there are two black aces in a deck of 52 cards.
Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
there are 4 aces in a deck, and 52 cards, so the probability is 4/52
There are four aces in a deck, one of each suit.
There are four aces in a 52 deck of cards. One is the ace of spades! One is the ace of clubs, one is the ace of hearts, and one is the ace of diamonds.
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