[original answer] four in 52!
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The question is not fully stated, but I assume what is being asked is "What are the chances of pulling all four aces out of 52 cards when four cards are drawn".
The answer is 1 / 270725 = 0.00000369 = 0.000369%. Approximately four out of one million.
The chances are (4*3*2*1) / (52*51*50*49) = 24 / 649700 = 1 / 270725. That is, on the first draw there is a 4/52 chance of drawing one of the four aces out of the full pack; In the 48 out of 52 cases where an ace isn't drawn, "you lose".
In the 4/52 cases where an ace is drawn first, there is a 3/51 chance of drawing one of the remaining three aces from the remaining 51 cards. If that happens, there is a 2/50 chance of drawing one of the remaining two aces from the remaining 50 cards; and then a 1/49 chance of drawing the last ace out of the remaining 49 cards.
[ If the question is "What are the chances of pulling any of the aces out of 52 cards in one draw" then "four in 52" is correct. ]
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Prob(At least one ace in ten cards out of 52) = 1 - Prob(No aces in ten cards out of 52) When you start there are 48 non-ace cards out of 52, At the next draw, there are 47 non-ace cards out of 51, and so on = 1 - (48/52)*(47/51)* ... *(39/43) = 1 - 0.41 = 0.59
There are four Aces in a standard deck of 52 cards. The probability, then, of not drawing an Ace is (52 - 4) in 52, or 48 in 52, or 12 in 13, or about 0.9231.
There are 4 Aces in a deck of 52 cards.4
There are two red aces in a deck of 52 cards.
There are four aces in a deck, one of each suit.