1/6
A fair cube has six faces numbered 1, 2, 3, 4, 5, 6 3 and 6 are multiples of 3 so you have 2 chances in 6 or 1 in 3 in it's simplest form
Chances=50% because on a 6 sided dice, as you have said, the sides are numbered 1,2,3,4,5 and 6. There are 3 even numbers and 3 odd numbers. Chances would be 3/6=50%
In one throw it is 1/3
2/6 which equals 1/3
Probability of coin heads up: 1/2 Rolling a 4 or 5 on the cube: 2/6 1/2 times 2/6 = 2/12, or 1/6.
1/6 x 1/6 = 1/36
Gary's chances of rolling either a 4 or a 6 are the same for any of the other numbers on the cube. The probability is 1 out of 3.
A fair cube has six faces numbered 1, 2, 3, 4, 5, 6 3 and 6 are multiples of 3 so you have 2 chances in 6 or 1 in 3 in it's simplest form
Chances=50% because on a 6 sided dice, as you have said, the sides are numbered 1,2,3,4,5 and 6. There are 3 even numbers and 3 odd numbers. Chances would be 3/6=50%
each number has 1 chance in 6 so rolling a 1 or a 2 is 1 chance in 3
The probabilities are 1/12, 0 and 0 respectively.
In one throw it is 1/3
That's going to depend on how many numbered sides the "cube" has, and howthey're numbered.If it's literally a six-sided cube, with the faces numbered 1 through 6, then the onlymultiple of 4 anywhere on it is 4, and the probability of rolling the 4 is1/6 or (16 and 2/3) percent.
2/6 which equals 1/3
Probability of coin heads up: 1/2 Rolling a 4 or 5 on the cube: 2/6 1/2 times 2/6 = 2/12, or 1/6.
the chances of rolling a 2 each time during 1 set of 3 rolls is -1 in 216- sets. i believe the formula is: 1 in 6 - the chance of rolling a"2" then multiply the chances for each separate roll 1/6 x 1/6 x 1/6 = 1/216
Sample space for rolling a number greater than 4 is {5,6} so 2 choices in total out of 6 P(>4)=2/6=1/3 is the answer