The probability of rolling one 6 is ( 1/6 ).The probability of rolling seven 6's is ( 1/6 )7 = 3.572 x 10-6 = 0.0003572 percent
The probability of rolling doubles on a fair six-sided die is 1/6. To roll doubles 7 times in a row, you would need to multiply this probability by itself 7 times, resulting in (1/6)^7. This equals approximately 1 in 78,364,164,096, which means the chances of rolling doubles 7 times in a row are extremely low.
1 in 100000000000000000000000000 or 10^26
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
The probability of rolling a 3 on a die are 1/6. Since each roll is an independent event, the probability of rolling a 3 4 times in a row is (1/6)4 or 1/1296.The odds of something happening are the chances of it happening vs. the chances of it not happening. The chance of not rolling a 3 4 times in a row is 1-(1/1296) or 1295/1296.Therefore the odds are 1:1295
The probability of rolling a six on a die 6 times in a row is 1 in 46,656, or 0.000021433. The calculate that, the probability of rolling one 6 is 1 in 6. Simply raise that to the sixth power to get 1 in 46,656.
Possible outcomes of a single dice are 6 ( 1,2,3,4,5,6) So if 5 such dices are rolled then the number of possible outcomes are 6 mulitiplied by 6 five times. 6x6x6x6x6x6=46656 possible outcomes.
You have a 3.125% chance of not rolling an even number, because each time you roll a die you have a 50% chance of not rolling an even number, but each additional time you roll a die your chances of not rolling an even number the formula changes from 3/6 to 3/12 because the possibilities double but your chances of not rolling an even remain the same so eventually we end up with 3/96 because of rolling the die 6 times.
The chance of rolling a double 6 is 1/6x1/6The chance of getting the 3 times in a row is(1/6x1/6)3 or (1/36)3 which is 1/46,656, a very small number!
the chances of rolling a 2 each time during 1 set of 3 rolls is -1 in 216- sets. i believe the formula is: 1 in 6 - the chance of rolling a"2" then multiply the chances for each separate roll 1/6 x 1/6 x 1/6 = 1/216
Prob(Rolling 2 when rolling 1200 times) = 1 - Prob(not rolling 2 when rolling 1200 times) = 1 - (5/6)1200 = 1 [accurate to 95 decimal places] That is, it is virtually a certainty.
If the dice is 6 sided, the chances of rolling each number is about 17% (100/6) If the dice is 4 sided, the chances of rolling each number is 25% (100/4) Similarly, 8 sided = 12.5% 10 sided = 10% 12 sided ≈ 8% 20 sided = 5%