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Their factors are:

125 = 1, 5, 25, 125

100 = 1, 2, 4, 5, 10, 20, 25, 50, 100

making their common factors: 1, 5, 25

Alternative method:

The prime factorisations are:

125 = 53

100 = 22 x 52

Therefore their common factors are the factors of the product of their common primes, ie:

Factors of 52 = 25 ⇒ 1, 5, 25

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13y ago

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