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1 ton = 2240 lb 10 ton = 10 x 2240 lb = 22400 lb
8 oz + 9 lb 8 oz = 10 lb 2 lb 4 oz + 10 lb = 12 lb 4 oz 8 oz + 2 lb 4 oz = 2 lb 12 oz
no 10 times more . 1 lb = 16 oz 10 lb = 160 oz 100 lb = 1,600 oz
29 lb
The volume of the block of ice is 2ft * 2ft * 2ft or 8 ft3. The equivalent weight of 8 cubic feet of water is 8ft3 * 62.5 lb/ft3 or 500 lbs. To find the weight of ice take 92% of the equivalent weight of water or 0.92 * 500 lbs = 460 lbs
A block of ice with the dimensions listed has a volume of 35ft^3. The density of ice at 32F is about 57.24 lb/ft^3. Multiplying the two together gives a mass of the ice of about 2003.4 lbs.
Varies on the variables... but short answer is about 1 degree...
1,2,3,4,5,6,7,8,9,10
I found that on a website selling a 379. BTW I'm not a trucker. DIMENSIONS GVW: 48,000 LB Front: 12,000 LB Rear: 36,000 LB W x H x L: 96" x 12' 10" x 29' 2" Wheelbase: 265" Cab to Axle: 83" from fairing 102" from sleeper (*Don't undestanding that..XD) Weight: Estimated: 18,000 LB
Depending on the mean temperature of the ice, it will require between 0.463 and 0.504 BTU's to raise the temperature of 1 lb. of ice for each deg. F. So, 5 lb of ice raised from 3 deg.F to 10 deg.F will require 5 x (10-3) x ~0.504 = ~17.64 BTU.
1 gallon of water weighs 8.34 lb so it will make 8.34 lb of ice
10% is equivalent to 1/10. 10% of 12000000 lb (1.2x107 lb) would be 1200000 lb (1.2x106 lb).
1 ton = 2240 lb 10 ton = 10 x 2240 lb = 22400 lb
18 stone and 9 lb.
1 pound
0.0376 lb/in³ 1 lb = ~26.6 in³ (approx dimensions: 2.98" x 2.98" x 2.98")
8 oz + 9 lb 8 oz = 10 lb 2 lb 4 oz + 10 lb = 12 lb 4 oz 8 oz + 2 lb 4 oz = 2 lb 12 oz