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Q: What are the dimensions of a 10 lb block of ice?
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What would a block of ice weigh if it was 5 ft by 7 ft by 12 in thick?

A block of ice with the dimensions listed has a volume of 35ft^3. The density of ice at 32F is about 57.24 lb/ft^3. Multiplying the two together gives a mass of the ice of about 2003.4 lbs.


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Depending on the mean temperature of the ice, it will require between 0.463 and 0.504 BTU's to raise the temperature of 1 lb. of ice for each deg. F. So, 5 lb of ice raised from 3 deg.F to 10 deg.F will require 5 x (10-3) x ~0.504 = ~17.64 BTU.


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How many 8 oz cups of ice in a 10 lb bag?

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How much will an 800 lb block of ice cool a pool?

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A 60lb block rests on a smooth plane incline at 20 with horizontal The block is pulled up the plane with a force of 30lb parallel to the plane What is the accelaration?

The component of the force parallel to the incline is 30 lb * sin(20°) = 10.27 lb. The net force on the block up the incline is 10.27 lb - frictional force. The frictional force is equal to the block's weight component parallel to the incline, which is 60 lb * sin(20°) = 20.53 lb. So, the net force causing acceleration is 10.27 lb - 20.53 lb = -10.26 lb. Using F = ma, the acceleration a = (-10.26 lb) / (60 lb) = -0.17 ft/s^2 down the incline.


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