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Q: What are the dimensions of a 10 lb block of ice?
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What would a block of ice weigh if it was 5 ft by 7 ft by 12 in thick?

A block of ice with the dimensions listed has a volume of 35ft^3. The density of ice at 32F is about 57.24 lb/ft^3. Multiplying the two together gives a mass of the ice of about 2003.4 lbs.


What are the dimensions of a frozen 25 lb turkey?

The dimensions of a frozen 25 lb turkey can vary depending on the brand and type of turkey. However, a typical frozen 25 lb turkey might have dimensions of approximately 18-20 inches in length, 12-14 inches in width, and 8-10 inches in height. It's important to note that these dimensions are approximate and can vary slightly.


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How many Btu's are needed to bring lbs of ice from - degree F to degree F?

Depending on the mean temperature of the ice, it will require between 0.463 and 0.504 BTU's to raise the temperature of 1 lb. of ice for each deg. F. So, 5 lb of ice raised from 3 deg.F to 10 deg.F will require 5 x (10-3) x ~0.504 = ~17.64 BTU.


How much ice will 1 gallon of water make?

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How many 8 oz cups of ice in a 10 lb bag?

To calculate the number of 8 oz cups of ice in a 10 lb bag, you first convert the weight of the bag to ounces. Since 1 lb is equal to 16 oz, a 10 lb bag is equivalent to 160 oz. Next, you divide the total weight by the weight of each cup of ice (8 oz) to find the number of cups. Therefore, a 10 lb bag of ice would contain 20 cups (160 oz ÷ 8 oz = 20 cups).


How much will an 800 lb block of ice cool a pool?

The exact amount of cooling will depend on several factors such as the size of the pool, the initial temperature of the water, and the ambient temperature. In general, an 800 lb block of ice will cool a pool, but it may not be sufficient to significantly lower the pool's temperature, especially if the pool is large or the weather is warm. It's best to consider using additional ice or a different cooling method for more effective results.


A 60lb block rests on a smooth plane incline at 20 with horizontal The block is pulled up the plane with a force of 30lb parallel to the plane What is the accelaration?

The component of the force parallel to the incline is 30 lb * sin(20°) = 10.27 lb. The net force on the block up the incline is 10.27 lb - frictional force. The frictional force is equal to the block's weight component parallel to the incline, which is 60 lb * sin(20°) = 20.53 lb. So, the net force causing acceleration is 10.27 lb - 20.53 lb = -10.26 lb. Using F = ma, the acceleration a = (-10.26 lb) / (60 lb) = -0.17 ft/s^2 down the incline.


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How much 1 lb ice weigh?

1 pound