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What are the dimensions of a garden with an area of 72 square feet and a perimeter of 36 feet?
Wiki User
∙ 11y ago
If the length and width are L and B feet, then
2(L + B) = 36 => L + B = 18 => L = 18 - B
L*B = 72 => (18 - B)B = 72
B2 - 18B + 72 = 0 => (B - 6)(B -12) = 0 => B = 6 or B = 12
B = 6 => L = 12 and B = 12 => L = 6
So the dimensions are 6 ft x 12 ft.
The dimensions are: length 12 feet and width 6 feet.
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Area = length x width
a x b = 72
Perimeter = 2 x length + 2 x width
2a+2b=36
The two equations can be solved by substituting a for b (a2-18a+72=0),
with the results a = 6 or 12 and b is the other
Wiki User
∙ 11y ago
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