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let the width of the rectangle by w cm

Then its length is w + 5 cm

→ perimeter = 2 x (w + (w + 5)) = 4w + 10

→ area = w(w + 5) = w^2 + 5w

but area = 2 x perimeter

→ w^2 + 5w = 2 x (4w + 10)

→ w^2 + 5w = 8w + 20

→ w^2 - 3w - 20 = 0

→ w = (3 + √89) ÷ 2 or (3 - √89) ÷ 2

The second leads to a negative length (≈ -3.22) which can't exist

→ the lengths are (3 + √89) ÷ 2 and (3 + √89) ÷ 2 + 5, ie

The rectangle is (3 + √89) ÷ 2 (≈ 6.22 cm) by (13 + √89) ÷ 2 (≈ 11.22 cm)

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Q: What are the dimensions of a rectangle when one side is greater than the other side by 5 cm and whose area is numerically twice its perimeter showing work?
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