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What are the dimensions of a rectangular room whose length is 7 feet longer than its width and whose area is 60 feet?
Wiki User
∙ 14y ago
Let w represent the width. The area of a rectangle equals the product of the length and width. From the statement of the problem, w(w + 7) = 60. Multiplying out the left side and rearranging gives w2 + 7w - 60 = 0. The number 60 can be factored into 12 X 5, which have a difference of 7. Therefore, this equation can be written as (w - 5)(w + 7), which is true when w has a value of 5 or -7. However, the length of a room can not be negative. Therefore, w is five and the width is 12, both in feet.
Wiki User
∙ 14y ago
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