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Private walks typically 3 ft wide. Public walks, 4 ft wide but vary by municipality and handicap accessibility.
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∙ 13y ago
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How do you calculate dimensions of a net of a prism?
Like you would a regular prism.
What is the definition of regular volume?
I assume it is the space (in 3 dimensions) that something occupies
You cannot tessellate five-sided regular polygons by themselves?
Mostly true - you cannot tessellate only regular pentagons in two dimensions, since you cannot sum up the intersection of the angles to 360 degrees. If you tessellate a regular pentagon in three dimensions, you end up with a dodecahedron.
How big is 250 sq ft in regular feet?
This question cannot be answered sensibly. A square foot is a measure of area, with dimensions [L2]. A [regular] foot is a measure of distance, with dimensions [L]. Basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information.
What is a pentagon in 3d?
A pentagon is a plane figure and has only two dimensions. It cannot have three dimensions.
How do you distinguish between derived dimensions and regular dimensions on the screen?
What you are looking for are driven dimensions. Derived dimensions must be a typo. Driven dimensions are enclosed in parentheses to distinguish them from regular dimensions in inventor. These dimensions do not contrain a sketch they simply reflect dimensioned geometry which is most likely under some geometric constraint.
What is the area of a regular polygon?
Impossible to figure out. You did not mention any dimensions of the figure. You mush have the dimensions.
What is the only regular 5 sided shape called?
In 2 dimensions, a regular 5 sided figure is a pentagon. In 3 dimensions, there is no regular sided 5 sided figure. The tetrahedron is a regular 4 sided figure and a cube is a regular 6 sided figure.
What do you think would happen if you spread regular table salt (sodium chloride) on an icy sidewalk?
it will melt
How do you calculate dimensions of a net of a prism?
Like you would a regular prism.
If a shape is regular it means?
A 2-dimensions regular polygon is one which has all its sides equal AND all its angles equal.
What is the definition of regular volume?
I assume it is the space (in 3 dimensions) that something occupies
You cannot tessellate five-sided regular polygons by themselves?
Mostly true - you cannot tessellate only regular pentagons in two dimensions, since you cannot sum up the intersection of the angles to 360 degrees. If you tessellate a regular pentagon in three dimensions, you end up with a dodecahedron.
How big is 250 sq ft in regular feet?
This question cannot be answered sensibly. A square foot is a measure of area, with dimensions [L2]. A [regular] foot is a measure of distance, with dimensions [L]. Basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information.
Finding dimensions of area of 190 in?
190 in is a length, not an area. Even if you were given an area, unless it was in the form of a regular shape you would not be able to determine its dimensions.
What is a pentagon in 3d?
A pentagon is a plane figure and has only two dimensions. It cannot have three dimensions.
A cement sidewalk will be poured around the outside of a rectangular plot that is 13m by 20 m what will be the area of the sidewalk if it is 1 meter wide?
Figure it like this: Because each side of the rectangular plot will have a one-meter wide sidewalk adjoining it, you know that the sidewalk, on each side of the plot will be two meters longer than the plot's dimensions. However, if you figured the length by adding the areas of each length of sidewalk, you would be wrong, because each length of sidewalk shares two corners with the adjacent lengths. Each corner is one square meter, and each length of sidewalk without two corners is the same as the dimension of the plot, times one meter. So essentially, you just add the plot dimensions and then add four. In other words, 2(13m * 1m) + 2(20m * 1m) + 4m2 = 26m2 + 40m2 + 4m2 = 70m2. Another way to figure it would be to figure the area which will be enclosed by the outer edge of the sidewalk (again, two meters longer than the plot on each side), and subtract the area of the plot itself, or: (15m * 22m) - (13m * 20m) = 330m2 - 260m2 = 70m2.
