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There is not enough information to provide an answer. The woe equations that are given can only be used to find the value for two of the three measures required.

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Q: What are the dimensions of a table with surface area of 2500 and a volume of 2500?
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Which is the larger volume 2.5 microliters or 2500 nanometers?

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If a box is to contain 2500 cubinc inches of material what is the least amount of cardboard needed to construc the box?

You first have to determine what box has the greatest volume to surface are ratio. People setting such questions usually are rather unimaginative and think "Boxes are all essentially like cubes" and never consider that a box could be a sphere or cylinder.So,For a cube:Area of Surface: 6 x L2Volume: L3 Where V = 2500, L=13.5Ratio (Volume/surface): L/6 = 2.26For a Sphere:Area of Surface: 4pi R2Volume: (4/3) pi R3 Where V= 2500, R= 8.59 (approx)Ratio (Volume/surface): (1/3)R = 2.86(R=radius in inches)From this we can see you contain more volume with a given amount of cardboard if it is made into a sphere than a cube. This a well known property of spheres.The question is then, what is the surface area of the sphere containing that volume. Just reorganize the equations for volume and area to get:A = 4 pi R2 where using the formula for volume of spheres R = (2500 x(0.75)x(1/pi))1/3 or A=4 pi ((2500x(0.75)x(1/pi))1/3)2Simply solve for A

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