This question needs a serious spell check. It then needs a serious edit to make clear what it is asking!
It is 36 ft * 2 ft - a very unlikely shape for a garden!
Well, darling, if the area of the garden is 11 square feet, the dimensions could be 1 foot by 11 feet, 2 feet by 5.5 feet, or even 3 feet by 3.67 feet. As long as you multiply the length and width together and get 11, you're good to go. Math doesn't have to be a garden of thorns, honey!
621 square feet
The dimensions would be 40 feet by 40 feet.
16 square feet
Then each side of the garden is 5 feet in length.
It is 12 square feet
If the area of the garden is 81 square feet and the perimeter is 36 feet, the solution is that the garden is a square 9 feet x 9 feet, where 4 x (side) =36.
Find the square root. For example, 25 sq. ft can be visualized as a 5 foot square, since 5 is the square root of 25. Often, you can factor the square foot dimension to help you visualize the area. For example, 32 square feet : 8 x 4 = 32 A sheet of plywood 8 feet long and 4 feet wide covers an area of 32 square feet.
12 feet square equals 124 square feet garden 11ftx11ft equals 121 square ft garden
Each side is 5.5 feet and 4 times 5.5 = 22 feet which is the perimeter of the garden
A square garden shape of 25 square feet could be 5 feet long by 5 feet width. There are other possibilities.