184
92,2
46,2,2
23,2,2,2
cos Jesse said they had to have them
The recursion tree for the function t(n) 4t(n/2) n has a branching factor of 4 at each level, with each node representing a subproblem of size n/2. The height of the tree is logn, and the total number of nodes in the tree is O(n).
Santa Claus
The median of a single n umber is the number itself: so 37.
You can try 1 slash / and the n umber 2 1/2
Suppose you have a number N and you want to find its largest prime factor. It is probably easiest to start at the bottom.Find the smallest prime factor, p.Find its factor pair = N/p.If the second number (= N/p) is a prime, then it is the largest prime factor.if not, replace N by N/p and go back to the top.
The only prime n umber between 20 and 25 is 23.
multiply the number you are 'squaring,' by itself 4 x 4 = 16 42 = 16
Easy way to remember: MEAN M ean E quals A verage N umber
channel 184
473 + 286 + n = 943 n = 943 - 473 - 286 n = 184
A tree with n vertices has n-1 edges.