There are no factors in the normal sense of the term "factor", but ...
Suppose a and b are the factors.
Then a+b=7 so that b = 7-a
Also a*b = -24 so that a*(7-a) = -24
ie a2 - 7a - 24 = 0
The roots of this quadratic are 1/2*[7 +/- sqrt(72 + 4*1*24)]
= 1/2*[7 +/- sqrt(145)] which gives the two factors given above.
3 and 4 are factors of -24.
1 and 6 are factors of -24.
To find the common factors of 14 and 98, we first list the factors of each number. The factors of 14 are 1, 2, 7, and 14, while the factors of 98 are 1, 2, 7, 14, 49, and 98. The common factors are 1, 2, 7, and 14. To find the sum of these common factors, we add them together: 1 + 2 + 7 + 14 = 24.
Composite factors of 24 are 4, 6, 8, 12 and 24. Sum of composite factors = 4+6+8+12+24 = 54.
60
It is 24.
The factors of 91 are: 1 7 13 91.The prime factors are: 7 x 13The sum of the prime factors = 7 + 13 = 20
24 and 16 are factors of 48
31
It's not entirely clear from the wording of your question what it is you want to know. Seven is a one-digit number. The sum of its digits is 7. Seven has two factors: 1 and 7. That sum is 8.
36 and 24
All of the [positive] whole-number factors of 24 are: 1, 2, 3, 4, 6, 8, 12, and 24. Their sum is 60.
3 and 21.
The prime factors of 28 are 2 and 7. Their sum is 9.