18a2 + 16a + 38
= 3(6a2 + 8a + 19)
244
57 + 57 + 38 + 38 = 190
You're looking for factors of 38 that have a difference of 17. Luckily, 38 only has two factor pairs. It's not 38 and 1. (y - 2)(y + 19)
The solution to the factorization - the factors are 1, 2, 19, 38
The factors of 38 are 1, 2, 19, and 38.
The factors of 38 are: 1, 2, 19, 38
The factors of 38 are: 1, 2, 19, 38 The factors of 71 are: 1, 71
The factors of 38 are: 1, 2, 19, 38 The factors of 76 are: 1, 2, 4, 19, 38, 76
The factors of 38 are 1, 2, 19, and 38. There are four different factors. The prime factors of 38 are 2 and 19. There are two different prime factors.
15 plus 38 is 53
The factors of 34 are 1, 2, 17, and 34. The factors of 38 are 1, 2, 19, and 38.
445