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What are the factors and prime factors of 21 in expodential form?
1, 3, 7, 21 3 and 7 are prime. 3 x 7 is the prime factorization. No exponents are required.
What is the prime factorization for 21 using exponents if possible?
3 x 7 = 21 No exponents necessary.
What are the factors of 1085 using exponents?
The factors are: 5 x 7 x 31 No exponents required.
What are the prime factors of 725 using exponents?
the prime factors of 725 using exponents are 5^2 x 29
What are the prime factors of 94 in exponents?
There are no exponents. The prime factors are 2 and 47, so the factorization is just 2 x 47.
What are the prime exponents of 34?
The prime factors of 34 are 2 and 17. No exponents are needed.
What is 666 in exponents?
As a product of its prime factors in exponents: 2*32*37 = 666
How do you write 630 with prime numbers and exponents?
First you separate it into prime factors (start looking for small factors, such as 2, 3, 5). Then, you combine the factors with exponents.
What is the prime factorization of 108 232 and 168?
As a product of its prime factors in exponents: 22*33 = 108 As a product of its prime factors in exponents: 23*29 = 232 As a product of its prime factors in exponents: 23*3*7 = 168
Prime factorization of 42 using exponents?
Prime factors of 42 are 2 x 3 x 7. Using exponents, which is totally unnecessary when a number is to the first power, this would be 21 x 31 x 71.
What is the prime factorization using exponents of 21?
The prime factorization of 21 can be expressed as 3^1 * 7^1, where 3 and 7 are both prime numbers. This means that 21 can be broken down into the product of these prime factors raised to their respective exponents. In other words, 21 is the result of multiplying 3 by 7.
What are the factors of 105 using exponents?
(1, 105) (3, 35) (5, 21) (7, 15)
