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Q: What are the factors of 4x3 plus 10x2 plus 2x plus 5?

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4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)

Whatever isn't 5(x - 1)(2x + 3)

10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)

This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.

(5x - 4)(2x + 7)

10x2

(5x - 4)(2x + 3)

(2x + 7)(5x - 4)

2x(2x2 - 9x + 5)

10x2 + 21x - 10 = 10x2 + 25x - 4x - 10 = 5x(2x + 5) - 2(2x + 5) = (2x + 5)(5x -2)

10x2

10x2

That's not as problem, unless you're practicing the procedure to simplify fractions.(10x2 - 2x)/(4x) = (10x2)/(4x) - (2x)/(4x) = 2.5x - 0.5

(x^2 - 2x - 2)(x^2 - 2x + 3)

If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5

(2x)2(x) = 4x3

5x(2x - 3)

(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1

I think there's something missing here, but as written that's 26x - 4x^3 which factors to -2x(2x^2 - 13)

(2x+3)(x+3)

2x**3-10x**2+3x-15 2x**2(x-5)+3(x-5) (2x**2+3)(x-5)

-2x(x + 3)(x + 2)

(2x + 1)(5x - 6)

2x

8x2 + 2x - 1 = (4x - 1)(2x + 1).