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Q: What are the factors of the equation 2x2 plus 10 equals 9x?

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It is a quadratic equation that has 2 solutions

2x2 + 3x - 20 = (x + 4)(2x - 5).

The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842

2x2 equals 5

2x2 - 5x - 3 = 0 This equation can be factored : (2x + 1)(x - 3) = 0

There are no powers e.g 2x2 would be due to the 2

6.50 to the nearest hundredth (4.685 & 1.815)

3

Using the quadratic equation formula: x = 1 or x = -10

None because the discriminant of this quadratic equation is less than zero.

4 equals 2x2, 6 equals 2x3

2x2 + 11x + 15 = (x + 3)(2x + 5).

By using the quadratic equation formula: x = -5 and x = 3

This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7

-7

Factors are (2x + 1)(x + 4), making x either -0.5 or -0.25

x2 + x2 = 2x2

No.

2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation

8 - 2x2 = x + 22 - 7Combine like terms on the right side:8 - 2x2 = x + 15Subtract 8 from each side:-2x2 = x + 7Add 2x2 to each side:0 = 2x2 + x + 7

It can't be solved because its discriminant is less than zero

If: 2x2 = 4 Then: x = the square root of 2

The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.

22 = 4

2x2=4x4=16