It is a quadratic equation that has 2 solutions
I'm assuming the question is: 2x2 = 24x x = 0 or x = 12
2x2 + 11x + 15 = (x + 3)(2x + 5).
Neither of the solutions appears on the list you provided along with the question.
There are no real solutions. The discriminant (b squared -4ac) is less than 0, so there are 2 imaginary solutions and 0 real ones.
It is a quadratic equation that has 2 solutions
It has two equal solutions for x which are x = 2 and x = 2
2x2 equals 5
3
I'm assuming the question is: 2x2 = 24x x = 0 or x = 12
2x2 - 3 = 13 So 2x2 = 16 x2 = 8 So that x = ±2√2
2x2 + 11x + 15 = (x + 3)(2x + 5).
Neither of the solutions appears on the list you provided along with the question.
8 - 2x2 = x + 22 - 7Combine like terms on the right side:8 - 2x2 = x + 15Subtract 8 from each side:-2x2 = x + 7Add 2x2 to each side:0 = 2x2 + x + 7
There are no real solutions. The discriminant (b squared -4ac) is less than 0, so there are 2 imaginary solutions and 0 real ones.
-7
The variable term, X^3, is a third order polynomial term and will render three solutions, though one of those may be zero.