The prime factors of 243 are
3 * 3 * 3 * 3 * 3
So 243 = 3^5
As a product of its prime factors in exponents: 22*32 = 36
The factors of 49 are: 1 7 49 The prime factors are: 7 x 7
243 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 8 factors of 243 are 1,2,3,4,9,27,81, and 243.The factor pairs of 243 are 1 x 243, 3 x 81, and 9 x 27.The proper factors of 243 are 1, 3, 9, 27, and 81 or,if the definition you are using excludes 1, they are 3, 9, 27, and 81.The prime factors of 243 are 3, 3, 3, 3, and 3. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factor (listing each prime factor only once) of 243 is 3.The prime factorization of 243 is 3 x 3 x 3 x 3 x 3 or, in exponential form, is 35.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
No, it's not. 243 is divisible by 3 and 81. To be prime, a number's only factors must be 1 and itself.
It has only one prime factor which is 3 and as a product of its prime factors: 3^5 = 243
prime number if it only has less than 2 factors
You have asked for an answer without stating the question. Since it is in the Prime Numbers category, you may be wanting to know the prime factors of 243. Prime factors of 243 are 3 x 3 x 3 x 3 x 3 or 35.
The factors of 729 are: 1 3 9 27 81 243 729The prime factor is 3
2 and 3
2 and 5
Just 2
2 and 19