30, 60, 90
The first 10 multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, and 30.
The first 10 multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, and 30.
30, 60, 90
30, 60, 90
30, 60, 90
5 + 10+15+20=50 ans
30, 60, 90
the first three multiples are 6, 12, 18.
The first 50 multiples of 6 are the first fifty even multiples of 3.
10 is.
they r 90, 180 and 270
To find the probability of selecting a multiple of 2 or 3 from the numbers 1 to 10, first identify the multiples: the multiples of 2 are 2, 4, 6, 8, and 10; the multiples of 3 are 3, 6, and 9. The number 6 is counted in both categories, so the unique multiples of 2 or 3 are 2, 3, 4, 6, 8, 9, and 10, totaling 7 unique numbers. Since there are 10 possible selections, the probability is 7/10 or 0.7.