1, 2, 4.
The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56.
56, 84, 112
No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56
The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.
first three common factors of 3,4,5
1,2,4,7,8,14,28,and 56 are the factors of 56 1,2,3,4,6,7,12,14,21,28,42,and 84 are the factors of 84. wait did you mean 56 and 84 or the number 5684?
28, 56, 84.
To get the gcf of 56 and 48, you have to split the numbers into their prime factors: 56 = 2x2x2x7 48 = 2x2x2x2x3 Next you have to spot any common prime factors. In this case both numbers have three 2s as prime factors. Multiply these together and you get: 2x2x2 = 8 And so the GCF of 56 and 48 is 8.
Factors of 56: 1, 2, 4, 7, 8, 14, 28, 56.Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42.Factors of 98: 1, 2, 7, 14, 49, 98.GCF (56, 42, 98) = 14
First, find the factors:56 = 23*748 = 24*364 = 26Then, multiply the factors, only using like factors once:LCM = 26*3*7 = 1344
30 is the first with three distinct prime factors.
Factors of 21 are 1,3,7,21 Factors of 56 are 1,2,4,7,8,14,28,56.