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Q: What is 19 plus 14x - 7x plus 1?

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7x(3x3 - 2x2 + 5x + 1)

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7(x - 1)(x + 3)

7x + 1 = 20 7x = 19 x = 19/7 x = 2.714285 recurring (that is, 2.714285714285..)

-x - 2 + 15x = 14x - 2 = 2(7x - 1)

Dividing all terms by 2 gives: 6x2+7x+2 = (2x+1)(3x+2) when factored

7x/4 = 1/8 (7x/4) x (8) = (1/8) x (8) 14x = 1 x = 1/14

Let the consecutive multiples of 7 be 7x and 7(x+1).7x + 7(x+1) = 1267x + 7x + 7 = 12614x + 7 + 12614x = 126 - 714x = 119x = 119/14x = 8.5For 7x to be a multiple of 7, x must be a whole number, so there are no such consecutive multiples.

2y + 7x + y-1?

(14x)(x)+1 14x^2 + 1

(12x3 + 14x2 + 14x + 2)/(4x + 2) simplify= (6x3 + 7x2 + 7x + 1)/(2x + 1)1. 6x3 + 7x2 - 3x2(2x + 1) = 6x3 - 6x3 + 7x2 - 3x2 = 4x2; bring down 7x2. 4x2 + 7x - 2x(2x + 1) = 4x2 - 4x2 + 7x - 2x = 5x bring down 13. 5x + 1 - 2(2x + 1) = 5x - 4x + 1 - 2 = x - 1 the reminderThus, (6x3 + 7x2 + 7x + 1)/(2x + 1) = 3x2 + 2x + 2 + (x - 1)/(2x + 1)and(12x3 + 14x2 + 14x + 2)/(4x + 2) = 3x2 + 2x + 2 + (2x - 2)/(4x + 2).

The three terms are 3x2, 7x and 1

7x + 2

8x^2 + 14x + 3 factors to (4x + 1)(2x + 3)

x2 + 7x + 6 = (x + 6) (x + 1)

7x(3x3 - 2x2 + 5x + 1)

7x + 7 = 7(x + 1)

The answer to the math problem -3 7x plus 7 is x equals 1/3.

2x^2+7x+5=(2x+5)(x+1)

5x2+ 7x + 2 = (x + 1)(5x + 2).

x^2 +7x+6 = (x+1)(x+6) when factored

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(4x + 1)(2x + 3)

It is: x-1+4+7x-3 = 8x simplified

(6x + 1)(x + 1)