Neglecting air resistance, the components of acceleration of an object that's dropped, tossed,
pitched, flung, lobbed, heaved, launched, or shot are constant.
The horizontal component is zero.
The vertical component is 9.8 meters per second2, directed downward.
These are both constant throughout the object's trajectory.
Physics The maximum absolute value of a periodically varying quantity. Mathematicsa: The maximum absolute value of a periodic curve measured along its vertical axis.b: The angle made with the positive horizontal axis by the vector representation of a complex number.
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
Steel? Aluminium?As a column (vertical leg) or a horizontal beam?In both cases the length and the method of fixing/supporting the ends will determine the maximum allowable load.
You have to know how long it takes to get to 90 mph to solve this. Speed = acceleration x time
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.
That varies depending on the monitor. You will have to read the specifications of the specific monitor that you want the answer for. There is no fixed maximum value.
One horizontal cut, one vertical cut (north-south), one vertical cut (east-west). That will get you 8 pieces.
If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.
Assuming the simple model where the object is projected with an initial velocity of u metres/second at an angle of x to the horizontal, and that the only force acting on it after that is gravitational acceleration, g = 9.81 metres/second^2, then h = [u*sin(x)]^2/(2*g) metres.If the launch is vertical then x = pi/2 radians and h = u^2/(2*g) metres.
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
the acceleration is equal to energy that release by the friction that came be electic that travel form somewhere.It proves that maximum acceleration rate.The easy explainationof that is Energy and Velocity are equal to maximum of acceleration
When a pendulum reaches its maximum elongation the velocity is zero and the acceleration is maximum
-- We can't say anything about the velocity, because we don't know anything about the horizontal motion of the ball. With the information included in the question, we can only be sure of how the vertical component of velocity behaves. -- At the maximum altitude of the ball, there's the instant where its vertical speed changes from upward to downward. At that instant, its vertical speed is zero.
Physics The maximum absolute value of a periodically varying quantity. Mathematicsa: The maximum absolute value of a periodic curve measured along its vertical axis.b: The angle made with the positive horizontal axis by the vector representation of a complex number.
The maximum speed of a fired projectile, unless fired downward in a vacuum, is the muzzle velocity - this is when the propulsive acceleration ceases. Ignoring air resistance, the projectile would maintain its horizontal velocity, while gravity would first reduce then restore the vertical component. Terminal velocity, the maximum possible atmospheric speed, is determined by mass, gravity, air density, and projectile shape, as gravitic acceleration is slowed by air resistance.
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
Mass= 2000 kg Acceleration=0.5m/s2 force = mass * acceleration =2000*0.5 N =1000 N