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What are the horizontal and vertical components of the acceleration vector at the maximum height?
Neglecting air resistance, the components of acceleration of an object that's dropped, tossed,
pitched, flung, lobbed, heaved, launched, or shot are constant.
The horizontal component is zero.
The vertical component is 9.8 meters per second2, directed downward.
These are both constant throughout the object's trajectory.
What else can I help you with?
What is the definition for amplitude?
Physics The maximum absolute value of a periodically varying quantity. Mathematicsa: The maximum absolute value of a periodic curve measured along its vertical axis.b: The angle made with the positive horizontal axis by the vector representation of a complex number.
How can you used trigonometry in projectile motions?
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
How much weight can a 2 x 2 angle support?
Steel? Aluminium?As a column (vertical leg) or a horizontal beam?In both cases the length and the method of fixing/supporting the ends will determine the maximum allowable load.
What is the maximum acceleration of a train with a maximum speed of 90 miles per hour?
You have to know how long it takes to get to 90 mph to solve this. Speed = acceleration x time
What is the condition for maximum velocity?
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.
Why does 45 degrees give maximum range?
When an object is launched at a 45-degree angle, it splits the initial velocity into horizontal and vertical components equally. This allows for the maximum range because the horizontal component remains constant throughout the flight, while the vertical component decreases due to gravity. This balance between horizontal and vertical components at 45 degrees results in the maximum distance traveled before hitting the ground.
When projectile has maximum horizontal range?
A projectile has maximum horizontal range when it is launched at an angle of 45 degrees to the horizontal. This angle allows for the ideal balance between the horizontal and vertical components of the projectile's velocity, ensuring that it travels the farthest distance before hitting the ground.
How does angle of projection affect the maximum height?
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
In projectile motion What Angle would horizontal and vertical distance be equal?
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
What is the process for solving a physics projectile problem?
To solve a physics projectile problem, you typically follow these steps: Identify the known variables, such as initial velocity, angle of launch, and acceleration due to gravity. Break down the motion into horizontal and vertical components. Use kinematic equations to calculate the time of flight, maximum height, and range of the projectile. Apply trigonometry to find the horizontal and vertical components of the velocity at any given time. Use these components to solve for the desired quantities, such as final velocity or position at a specific time. By following these steps and applying the appropriate equations, you can successfully solve a physics projectile problem.
How can one determine the maximum height reached by a projectile?
To determine the maximum height reached by a projectile, you can use the formula: maximum height (initial vertical velocity)2 / (2 acceleration due to gravity). This formula calculates the height based on the initial vertical velocity of the projectile and the acceleration due to gravity.
Is the maximum number of horizontal and vertical pixels that can be displayed on a screens?
That varies depending on the monitor. You will have to read the specifications of the specific monitor that you want the answer for. There is no fixed maximum value.
What is the proof that 45 degrees provides the maximum range for projectile motion?
The proof that 45 degrees provides the maximum range for projectile motion is based on the fact that at this angle, the horizontal and vertical components of the initial velocity are equal. This results in the projectile traveling the farthest distance before hitting the ground.
What are the two types of motion a projectile has?
If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.
What are some common projectile motion problems and what are the solutions to these problems?
Common projectile motion problems include determining the maximum height reached by an object, the time of flight, the range of the projectile, and the velocity at a certain point. Solutions to these problems involve breaking down the motion into horizontal and vertical components, using kinematic equations to calculate the necessary parameters, and applying the principles of projectile motion such as the independence of horizontal and vertical motion.
How do you find projectile motion?
Projectile motion is a form of motion in which a projectile is thrown near the earth's surface. When thrown, the projectile moves along a curved path because of gravity. An example of projectile motion is a sprinkler shooting water into the air and the water falling back down to Earth.
What happens when you increase the horizontal velocity to the maximum in a projectile motion?
Increasing the horizontal velocity to the maximum in a projectile motion will cause the object to travel further horizontally before hitting the ground. This is because the horizontal velocity determines how far the object will travel in the horizontal direction before gravity pulls it down. The vertical motion of the object will remain the same, but the increased horizontal velocity will result in a longer horizontal distance traveled.
