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To solve this, you need to know the odds of getting one tie in RPS. Note that there are nine possible outcomes when two people play one round, and that it is a tie only when both players throw the same thing:

X R P S

R T N N

P N T N

S N N T

Where N means "no tie" and T means "tie"

So the odds of getting a tie a single time are 3/9=1/3. Now, the odds of getting 21 consecutive ties is going to be (1/3)^21, as you multiply the probability of an event happening with itself to see the chances of it happening consecutively. With this the odds come to 1/10460353203

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Q: What are the mathematical odds of getting 21 consecutive ties in rock paper scissors?
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