The molality is 5,54.
30.1 percent by mass = 30.1 g HCOOH + 69.9 g H2Omoles HCOOH = 30.1 g x 1 mol/46 g = 0.654 molesmoles H2O = 69.9 g x 1 mol/18 g = 3.88 molesTotal moles = 4.53mole fraction HCOOH = 0.654/4.53 = 0.144mole fraction H2O = 3.88/4.53 = 0.856molality = moles solute/kg solvent = 0.654/0.0699 = 9.36 m
Percent concentration could mean many things...MOLARITY is defined as the moles of solute per unit volume of solution so 5 moles of NaCl in one liter of solution would be 5M (molar) NaCl solution.(Note: Solution is the solvent and solute combined, usually the solid is added and then the solution is filled to a certain line once the solid has dissolved.)MOLALITY is defined as the moles of solute per kilogram of solvent (NOT solution). So 5 moles of NaCl in one kilogram of water makes 5 mol/kg NaCl. (sometimes the symbol m is used for molality but is often confused with the unit of meters).For other types of "percent concentration" of solutions check:http://en.wikipedia.org/wiki/ConcentrationA cursory glance seemed to confirm the accuracy of the information.
The cell of Gram+ bacteria will break down against lysozyme and the cell will be injured but when it placed in sucrose the nutrient will be absorbed by the surface
138 g NaCl 1.10 L= 1100mL 1100mL x 1.08g/mL = 1188 grams TOTAL 138/1188 x 100 = 11.6%
10 gallons..
The mole fraction of HCl in 20 percent aqueous solution is 0.21.
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
5.84 M
The mole fraction of HCl is 0.34.
Assuming that is is a solution of glucose in water, the answer is 93%.
Formalin is 40% solution of formaldehyde not an acid.
30.1 percent by mass = 30.1 g HCOOH + 69.9 g H2Omoles HCOOH = 30.1 g x 1 mol/46 g = 0.654 molesmoles H2O = 69.9 g x 1 mol/18 g = 3.88 molesTotal moles = 4.53mole fraction HCOOH = 0.654/4.53 = 0.144mole fraction H2O = 3.88/4.53 = 0.856molality = moles solute/kg solvent = 0.654/0.0699 = 9.36 m
100 g of solution containing 50 g of NaOH.
40% aqueous solution of formaldehyde is known as Formalin.
19
75gm