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The molality is 5,54.

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Q: What are the molality and mole fraction of solute in a 25.5 percent by mass aqueous solution of formic acid (HCOOH)?
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What are the molality and mole fraction of solute in a 30.1 percent by mass aqueous solution of formic acid (HCOOH)?

30.1 percent by mass = 30.1 g HCOOH + 69.9 g H2Omoles HCOOH = 30.1 g x 1 mol/46 g = 0.654 molesmoles H2O = 69.9 g x 1 mol/18 g = 3.88 molesTotal moles = 4.53mole fraction HCOOH = 0.654/4.53 = 0.144mole fraction H2O = 3.88/4.53 = 0.856molality = moles solute/kg solvent = 0.654/0.0699 = 9.36 m


What is Percent Concentration?

Percent concentration could mean many things...MOLARITY is defined as the moles of solute per unit volume of solution so 5 moles of NaCl in one liter of solution would be 5M (molar) NaCl solution.(Note: Solution is the solvent and solute combined, usually the solid is added and then the solution is filled to a certain line once the solid has dissolved.)MOLALITY is defined as the moles of solute per kilogram of solvent (NOT solution). So 5 moles of NaCl in one kilogram of water makes 5 mol/kg NaCl. (sometimes the symbol m is used for molality but is often confused with the unit of meters).For other types of "percent concentration" of solutions check:http://en.wikipedia.org/wiki/ConcentrationA cursory glance seemed to confirm the accuracy of the information.


What will happen when a gram positive bacterium is placed in a aqueous solution of lysozyme and 10 percent sucrose?

The cell of Gram+ bacteria will break down against lysozyme and the cell will be injured but when it placed in sucrose the nutrient will be absorbed by the surface


What is the mass percent of the solution. if An aqueous NaCl solution is made using 138 g of NaCl diluted to a total solution volume of 1.10 L Assume a density of 1.08 g per ml for the solution.?

138 g NaCl 1.10 L= 1100mL 1100mL x 1.08g/mL = 1188 grams TOTAL 138/1188 x 100 = 11.6%


How many gallons of a 12 percent indicator solution must be mixed with a 20 percent indicator solution to get 10 gallons of a 14 percent solution?

10 gallons..

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How do you find the mass percent mole fraction molality and molarity of a solution?

Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)


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What are the molality and mole fraction of solute in a 30.1 percent by mass aqueous solution of formic acid (HCOOH)?

30.1 percent by mass = 30.1 g HCOOH + 69.9 g H2Omoles HCOOH = 30.1 g x 1 mol/46 g = 0.654 molesmoles H2O = 69.9 g x 1 mol/18 g = 3.88 molesTotal moles = 4.53mole fraction HCOOH = 0.654/4.53 = 0.144mole fraction H2O = 3.88/4.53 = 0.856molality = moles solute/kg solvent = 0.654/0.0699 = 9.36 m


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40% aqueous solution of formaldehyde is known as Formalin.


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