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Q: What are the multiples of 4 6 and 9?

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The multiples of 6 is 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90.................. The multiples of 9 is 9,18,27,36,45,54,63,72,81,90,99,108,117,126,135...............

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No. For a start, 9 is itself a multiple of 9, but it is not a multiple of 6.In general, all multiples of a number "a" will also be multiples of number "b", only if "a" itself is also a multiple of "b". For example, all multiples of 12 are multiples of 4, since 12 is a multiple of 4.

There are plenty of common multiples, but only one can be the least; thus the least common multiple of 4, 6, 9 is 36.

4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.

3, 6, 9, 12

The lowest one is 36

No; all multiples are not multiples of 6, for example 3×3 = 9 is not a multiple of 6. However as 6 = 2×3 all multiples of 6 are also multiples of 3.

Multiples of 1- 1, 2 3, 4 ,5, 6, 7, 8, 9, 10-- Like counting Multiples of 2- 2,4,6,8,10,12, ect. Multiples of 3- 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54, Multiples of 4- Multiples of 5- Multiples of 6

Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72

3, 6, 9, and 12 are the first four integer multiples (products of 1, 2, 3, 4). 6, 9, 12, and 15 are the first four prime multiples (products of 2, 3, 4, 5).

The multiples of 3 are 3, 6, 9, 12, 15..... The multiples of 4 are 4, 8, 12, 16, 20.... The multiples is a number that can multiples by a number

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