3, 6, 9, 12, 15, 18 4, 8, 12, 16, 20, 24 6, 12, 18, 24, 30, 36 Common multiples include 12, 24, 36, 48, 60, 72
Take the multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, etc. Now, eliminate every fourth number in the sequence (the multiples of 4). The remaining numbers will be multiples of 3, but not of 4.
lcm(4, 9) = 36 → the two least common multiples (ie the first two common multiples) of 4 and 9 are 36 and 72.
The first 3 multiples of 4 are: 4, 8, and 12.The first 3 multiples of 9 are: 9, 18, and 27.
Yes, for example the multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, ......etc. (all even numbers are multiples of 2) or multiples of 3 are 3, 6, 9, 12, 15, 18, 21, ....... etc.
The multiples of 6 is 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90.................. The multiples of 9 is 9,18,27,36,45,54,63,72,81,90,99,108,117,126,135...............
Well, honey, let me break it down for you. No, not all multiples of 9 are multiples of 6. See, multiples of 9 are numbers like 9, 18, 27, and so on, while multiples of 6 are numbers like 6, 12, 18, and so forth. So, while 18 is both a multiple of 9 and 6, not all multiples of 9 will be multiples of 6. Hope that clears things up for ya!
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.
180
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
Multiples of 1- 1, 2 3, 4 ,5, 6, 7, 8, 9, 10-- Like counting Multiples of 2- 2,4,6,8,10,12, ect. Multiples of 3- 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54, Multiples of 4- Multiples of 5- Multiples of 6
The lowest one is 36
Do you mean 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12? Do you want multiples of each one separately? e.g. multiples of 2, multiples of 3, multiples of 4? The answers to the times tables will do it if that is what you want. eg 2, 4, 6, 8, 10... 3, 6, 9, 12, 15... 4, 8, 12, 16, 20... etc.
3, 6, 9, 12
the first 6 multiples of 9 are 9 , 18 , 27 , 36 , 45 , 54
Multiples of 6: 1,2,3,6 Multiples of 4: 1,2,4 Multiples of 3: 1,3
The common multiples of 6 and 9 are the infinite set of multiples of their LCM, which is 18. So the common multiples of 6 and 9 are 18, 36, 54, 72, 90, 108, 126, 144, 162, 180, and so on.