Two and three are relatively prime, or coprime. That means that they have no smaller number, or factor, in common. So, the multiples of both numbers are the multiples of the product of the two, or the multiples of six.
Multiples of 6.
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
3
There are six multiples of both 2 and 3 that fall between 1 and 40. They are: 6, 12, 18, 24, 30, 36.
Three of them.
6 and 12 are multiples of 2 & 3
Multiples of 6.
There is 67
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
3
There are six multiples of both 2 and 3 that fall between 1 and 40. They are: 6, 12, 18, 24, 30, 36.
No multiples of 2 are factors of 3.
Multiples of 6 are.
Three of them.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
It comes from the fact that 6 = 2 x 3 which means that all multiples of 6 must also be a multiple of both 2 and 3.
Multiples of 12A multiple of 3 and 4 is any number that both 3 and 4 go into.For example 12 and 24 are multiples of both three and four.