Two and three are relatively prime, or coprime. That means that they have no smaller number, or factor, in common. So, the multiples of both numbers are the multiples of the product of the two, or the multiples of six.
Multiples of 6.
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
3
There are six multiples of both 2 and 3 that fall between 1 and 40. They are: 6, 12, 18, 24, 30, 36.
To find all multiples of 3 and 4, we need to find the numbers that are divisible by both 3 and 4. The multiples of 3 are 3, 6, 9, 12, 15, 18, and so on. The multiples of 4 are 4, 8, 12, 16, 20, and so on. The common multiples of 3 and 4 are numbers that appear in both lists, such as 12. Therefore, the multiples of 3 and 4 are numbers that can be divided evenly by both 3 and 4, such as 12, 24, 36, and so on.
6 and 12 are multiples of 2 & 3
Multiples of 6.
There is 67
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
3
There are six multiples of both 2 and 3 that fall between 1 and 40. They are: 6, 12, 18, 24, 30, 36.
No multiples of 2 are factors of 3.
Multiples of 6 are.
To find all multiples of 3 and 4, we need to find the numbers that are divisible by both 3 and 4. The multiples of 3 are 3, 6, 9, 12, 15, 18, and so on. The multiples of 4 are 4, 8, 12, 16, 20, and so on. The common multiples of 3 and 4 are numbers that appear in both lists, such as 12. Therefore, the multiples of 3 and 4 are numbers that can be divided evenly by both 3 and 4, such as 12, 24, 36, and so on.
Three of them.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
It comes from the fact that 6 = 2 x 3 which means that all multiples of 6 must also be a multiple of both 2 and 3.