Multiples of 6.
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
3
There are six multiples of both 2 and 3 that fall between 1 and 40. They are: 6, 12, 18, 24, 30, 36.
To find all multiples of 3 and 4, we need to find the numbers that are divisible by both 3 and 4. The multiples of 3 are 3, 6, 9, 12, 15, 18, and so on. The multiples of 4 are 4, 8, 12, 16, 20, and so on. The common multiples of 3 and 4 are numbers that appear in both lists, such as 12. Therefore, the multiples of 3 and 4 are numbers that can be divided evenly by both 3 and 4, such as 12, 24, 36, and so on.
6 and 12 are multiples of 2 & 3
Multiples of 6.
There is 67
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
3
There are six multiples of both 2 and 3 that fall between 1 and 40. They are: 6, 12, 18, 24, 30, 36.
No multiples of 2 are factors of 3.
Multiples of 6 are.
To find all multiples of 3 and 4, we need to find the numbers that are divisible by both 3 and 4. The multiples of 3 are 3, 6, 9, 12, 15, 18, and so on. The multiples of 4 are 4, 8, 12, 16, 20, and so on. The common multiples of 3 and 4 are numbers that appear in both lists, such as 12. Therefore, the multiples of 3 and 4 are numbers that can be divided evenly by both 3 and 4, such as 12, 24, 36, and so on.
Three of them.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
It comes from the fact that 6 = 2 x 3 which means that all multiples of 6 must also be a multiple of both 2 and 3.