500 2500.
100 times because if you do the opposite with the numbers you have, 500/5=100
Multiply by 5 4*5 = 20 20*5 = 100 100*5 = 500 500*5 = 2500
100 + 300 + 500 + 500 + 600 = 2000. Then divide by 5 to get 400. The mean of these five numbers is 400.
0.8
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
Never mind guys I figured it out!
The sequence appears to involve multiplying the previous number by an increasing factor: (4 \times 5 = 20) and (20 \times 5 = 100). Following this pattern, the next number would be (100 \times 5 = 500), and then (500 \times 5 = 2500). Therefore, the next two numbers in the sequence are 500 and 2500.
200, 500 and 201.
100 times because if you do the opposite with the numbers you have, 500/5=100
500
40. There are 400 numbers between 100 and 500 and one in every ten ends in 5.
Three numbers that equal 500 could be 200, 200, and 100. If you add these numbers together (200 + 200 + 100), the sum is 500. Alternatively, any combination of numbers that adds up to 500 would also work, such as 250, 250, and 0.
Well First, you need 500 because 500/5 is obviuosly 100. 98+99+100+101+102= 500. Therefore, the consecutive whole numbers are 98,99,100,101,102! -Levizy123
100 + 300 + 500 + 500 + 600 = 2000. Then divide by 5 to get 400. The mean of these five numbers is 400.
Multiply by 5 4*5 = 20 20*5 = 100 100*5 = 500 500*5 = 2500
The 3 digit numbers under 500 are 100 through 499.
500